[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index] Re: IRQ latency measurements in hypervisor
On Thu, 2021-01-14 at 15:33 -0800, Stefano Stabellini wrote: > On Tue, 12 Jan 2021, Volodymyr Babchuk wrote: > > 2. RTDS scheduler. With console disabled, things like "hexdump -v > > /dev/zero" didn't affected the latency so badly, but anyways, > > sometimes I got ~600us spikes. This is not a surprise, because > > of > > default RTDS configuration. I changed period for DomU from > > default > > 10ms to 100us and things got better: with Dom0 burning CPU I am > > rarely getting max latency of about ~30us with mean latency of > > ~9us > > and deviation of ~0.5us. On other hand, when I tried to set > > period > > to 30us, max latency rose up to ~60us. > > This is very interestingi too. Did you get any spikes with the period > set to 100us? It would be fantastic if there were none. > This *probably* makes some sense. Where the *probably* comes from the fact that all the following reasoning assumes that what I recall about real-time scheduling theory is correct, on which I would not bet. Perhaps Stefano can ask to my good old friend Marko Bertogna, from the Univeristy of Modena, as they're collaborating on cache-coloring, what he his team think. He was already much better than me with this things, back in the days of the Ph.D... So for sure he's much better than me know! :-) Anyway, as I was saying, having a latency which is ~ 2x of your period is ok, and it should be expected (when you size the period). In fact, let's say that your budget is Xus, and your period is 30us. This means that you get to execute for Xus every 30us. So, basically, at time t0 you are given a budget of Xus and you are guaranteed to be able to use it all within time t1=t0+30us. At that time (t1=t0+30us) you are given another Xus amount of budget, and you are guaranteed to be able to use it all within t2=t1+30us=t0+60us. Now, with a period as small as 30us, your budget is also going to be pretty small (how much was that? If it was in your mail, I must have missed it). Are you sure that the vCPU is able to wake up and run until the point that your driver has done all the latency measurement in _just_one_ instance (i.e., all this takes less than the budget)?. In fact, lat's say your budget is 10us, and it the vCPU needs 15us for waking up and doing the measurements. At time t0 the vCPU is scheduler, and let's say that the latency at that time is exactly 0. The vCPU start to run but, at time t0+10us (where 10us is the budget) it is stopped. at time t1=t0+30us, the vCPU receives a budget replenishment but that does not mean that it will start to run immediately, if the system is busy. In fact, what RTDS guarantees is that the vCPU will be able to execute for 10us within time t2=t1+30us. So, in theory, it can start to run as far as t2-10us, without violating any guarantee. If that is, in fact, what happens, i.e., the vCPU starts to run only at t2-10us, and it is only then that it manages to finish computing and recording the latency (after running for 5us more, as we said it takes 15us). What it will therefore record would be a latency to t2-5us, which in fact is: t1 + 30us - 5us = t0 + 30us + 30us - 5us = = 0 + 60us - 5us = 55us ~= 60us So... May this be the case? Thanks and Regards -- Dario Faggioli, Ph.D http://about.me/dario.faggioli Virtualization Software Engineer SUSE Labs, SUSE https://www.suse.com/ ------------------------------------------------------------------- <<This happens because _I_ choose it to happen!>> (Raistlin Majere) Attachment:
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