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[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index] Re: [Xen-devel] [PATCH v2] x86/dom0: improve PVH initrd and metadata placement
On Wed, Mar 04, 2020 at 11:00:18AM +0100, Jan Beulich wrote:
> On 04.03.2020 10:53, Roger Pau Monné wrote:
> > On Tue, Mar 03, 2020 at 04:40:36PM +0100, Jan Beulich wrote:
> >> On 03.03.2020 12:52, Roger Pau Monne wrote:
> >>> --- a/xen/arch/x86/hvm/dom0_build.c
> >>> +++ b/xen/arch/x86/hvm/dom0_build.c
> >>> @@ -490,6 +490,45 @@ static int __init pvh_populate_p2m(struct domain *d)
> >>> #undef MB1_PAGES
> >>> }
> >>>
> >>> +static paddr_t find_memory(const struct domain *d, const struct
> >>> elf_binary *elf,
> >>> + size_t size)
> >>> +{
> >>> + paddr_t kernel_start = (paddr_t)elf->dest_base;
> >>> + paddr_t kernel_end = (paddr_t)(elf->dest_base + elf->dest_size);
> >>> + unsigned int i;
> >>> +
> >>> + for ( i = 0; i < d->arch.nr_e820; i++ )
> >>> + {
> >>> + paddr_t start, end = d->arch.e820[i].addr + d->arch.e820[i].size;
> >>> +
> >>> + /* Don't use memory below 1MB, as it could overwrite the
> >>> BDA/EBDA. */
> >>> + if ( end <= MB(1) || d->arch.e820[i].type != E820_RAM )
> >>> + continue;
> >>> +
> >>> + start = MAX(ROUNDUP(d->arch.e820[i].addr, PAGE_SIZE), MB(1));
> >>> +
> >>> + if ( end <= kernel_start || start >= kernel_end )
> >>> + ; /* No overlap, nothing to do. */
> >>> + /* Deal with the kernel already being loaded in the region. */
> >>> + else if ( kernel_start <= start && kernel_end > start )
> >>
> >> Since, according to your reply on v1, [kernel_start,kernel_end) is
> >> a subset of [start,end), I understand that the <= could equally
> >> well be == - do you agree? From this then ...
> >>
> >>> + /* Truncate the start of the region. */
> >>> + start = ROUNDUP(kernel_end, PAGE_SIZE);
> >>> + else if ( kernel_start <= end && kernel_end > end )
> >>
> >> ... it follows that you now have two off-by-1s here, as you changed
> >> the right side of the && instead of the left one (the right side
> >> could, as per above, use == again). Using == in both places would,
> >> in lieu of a comment, imo make more visible to the reader that
> >> there is this sub-range relationship between both ranges.
> >
> > Right, I agree to both the above and have adjusted the conditions.
> >
> >>> + /* Truncate the end of the region. */
> >>> + end = kernel_start;
> >>> + /* Pick the biggest of the split regions. */
> >>
> >> Then again - wouldn't this part suffice? if start == kernel_start
> >> or end == kernel_end, one side of the "split" region would simply
> >> be empty.
> >
> > That's why it's using an else if construct, so that we only get
> > here if the kernel is loaded in the middle of the region, and there
> > are two regions left as part of the split.
>
> But my question is - do we really need the earlier parts of
> this if/else-if chain? Won't this latter part deal find with
> zero-sized ranges at head or tail of the region?
Oh, I misread your reply sorry. Yes you are right, I can achieve the
same just with this last part.
Thanks, Roger.
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