[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index] [Xen-devel] [PATCH v2 14/20] rbtree: coding style adjustments
Set comment and indentation style to be consistent with linux coding style and the rest of the file, as suggested by Peter Zijlstra Signed-off-by: Michel Lespinasse <walken@xxxxxxxxxx> Cc: Andrea Arcangeli <aarcange@xxxxxxxxxx> Acked-by: David Woodhouse <David.Woodhouse@xxxxxxxxx> Cc: Rik van Riel <riel@xxxxxxxxxx> Cc: Peter Zijlstra <a.p.zijlstra@xxxxxxxxx> Cc: Daniel Santos <daniel.santos@xxxxxxxxx> Cc: Jens Axboe <axboe@xxxxxxxxx> Cc: "Eric W. Biederman" <ebiederm@xxxxxxxxxxxx> Signed-off-by: Andrew Morton <akpm@xxxxxxxxxxxxxxxxxxxx> Signed-off-by: Linus Torvalds <torvalds@xxxxxxxxxxxxxxxxxxxx> [Linux commit 7ce6ff9e5de99e7b72019c7de82fb438fe1dc5a0] Ported to Xen. Signed-off-by: Praveen Kumar <kpraveen.lkml@xxxxxxxxx> --- xen/common/rbtree.c | 44 ++++++++++++++++++++++++-------------------- 1 file changed, 24 insertions(+), 20 deletions(-) diff --git a/xen/common/rbtree.c b/xen/common/rbtree.c index 1fe059a568..1cbe9a53d7 100644 --- a/xen/common/rbtree.c +++ b/xen/common/rbtree.c @@ -367,16 +367,14 @@ void rb_erase(struct rb_node *node, struct rb_root *root) child = node->rb_right; else if (!node->rb_right) child = node->rb_left; - else - { + else { struct rb_node *old = node, *left; node = node->rb_right; while ((left = node->rb_left) != NULL) node = left; - if (rb_parent(old)) - { + if (rb_parent(old)) { if (rb_parent(old)->rb_left == old) rb_parent(old)->rb_left = node; else @@ -412,14 +410,12 @@ void rb_erase(struct rb_node *node, struct rb_root *root) if (child) rb_set_parent(child, parent); - if (parent) - { + if (parent) { if (parent->rb_left == node) parent->rb_left = child; else parent->rb_right = child; - } - else + } else root->rb_node = child; color: @@ -464,8 +460,10 @@ struct rb_node *rb_next(const struct rb_node *node) if (RB_EMPTY_NODE(node)) return NULL; - /* If we have a right-hand child, go down and then left as far - as we can. */ + /* + * If we have a right-hand child, go down and then left as far + * as we can. + */ if (node->rb_right) { node = node->rb_right; while (node->rb_left) @@ -473,12 +471,14 @@ struct rb_node *rb_next(const struct rb_node *node) return (struct rb_node *)node; } - /* No right-hand children. Everything down and left is - smaller than us, so any 'next' node must be in the general - direction of our parent. Go up the tree; any time the - ancestor is a right-hand child of its parent, keep going - up. First time it's a left-hand child of its parent, said - parent is our 'next' node. */ + /* + * No right-hand children. Everything down and left is + * smaller than us, so any 'next' node must be in the general + * direction of our parent. Go up the tree; any time the + * ancestor is a right-hand child of its parent, keep going + * up. First time it's a left-hand child of its parent, said + * parent is our 'next' node. + */ while ((parent = rb_parent(node)) && node == parent->rb_right) node = parent; @@ -493,8 +493,10 @@ struct rb_node *rb_prev(const struct rb_node *node) if (RB_EMPTY_NODE(node)) return NULL; - /* If we have a left-hand child, go down and then right as far - as we can. */ + /* + * If we have a left-hand child, go down and then right as far + * as we can. + */ if (node->rb_left) { node = node->rb_left; while (node->rb_right) @@ -502,8 +504,10 @@ struct rb_node *rb_prev(const struct rb_node *node) return (struct rb_node *)node; } - /* No left-hand children. Go up till we find an ancestor which - is a right-hand child of its parent */ + /* + * No left-hand children. Go up till we find an ancestor which + * is a right-hand child of its parent + */ while ((parent = rb_parent(node)) && node == parent->rb_left) node = parent; -- 2.12.0 _______________________________________________ Xen-devel mailing list Xen-devel@xxxxxxxxxxxxx https://lists.xen.org/xen-devel
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