Re: [Xen-devel] Host Numa informtion in dom0

[Andre Przywara <andre.przywara@xxxxxxx>]

Kamble, Nitin A wrote:
> Hi Keir,
>
>    Attached is the patch which exposes the host numa information to 
> dom0. With the patch “xm info” command now also gives the cpu topology & 
> host numa information. This will be later used to build guest numa support.
What information are you missing from the current physinfo? As far as I 
can see, only the total amount of memory per node is not provided. But 
one could get this info from parsing the SRAT table in Dom0, which is at 
least mapped into Dom0's memory.
Or do you want to provide NUMA information to all PV guests (but then it 
cannot be a sysctl)? This would be helpful, as this would avoid to 
enable ACPI parsing in PV Linux for NUMA guest support.
Beside that I have to oppose the introduction of sockets_per_node again. 
Future AMD processors will feature _two_ nodes on _one_ socket, so this 
variable should hold 1/2, but this will be rounded to zero. I think this 
information is pretty useless anyway, as the number of sockets is mostly 
interesting for licensing purposes, where a single number is sufficient. 
 For scheduling purposes cache topology is more important.
My NUMA guest patches (currently for HVM only) are doing fine, I will 
try to send out a RFC patches this week. I think they don't interfere 
with this patch, but if you have other patches in development, we should 
sync on this.
The scope of my patches is to let the user (or xend) describe a guest's 
 topology (either by specifying only the number of guest nodes in the 
config file or by explicitly describing the whole NUMA topology). Some 
code will assign host nodes to the guest nodes (I am not sure yet 
whether this really belongs into xend as it currently does, or is better 
done in libxc, where libxenlight would also benefit).
Then libxc's hvm_build_* will pass that info into the hvm_info_table, 
where code in the hvmloader will generate an appropriate SRAT table.
An extension of this would be to let Xen automatically decide whether a 
split of the resources is necessary (because there is not enough memory 
available (anymore) on one node).
Looking forward to comments...

Regards,
Andre.

--
Andre Przywara
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